CUET · PHYSICS · PYQ PAPER 2025
A proton moves from south to north with a speed of \( 2 \times 10^7 \, \text{m/s} \). When a magnetic field is applied from west to east, the proton gets an acceleration of \( 10^{12} \, \text{m/s}^2 \). The mass of the proton is \( 1.6 \times 10^{-27} \, \text{kg} \). The value of the magnetic field is:
- A \( 1.5 \times 10^{-4} \, \text{T} \)
- B \( 2.5 \times 10^{-5} \, \text{T} \)
- C \( 3.1 \times 10^{-3} \, \text{T} \)
- D \( 4.1 \times 10^{-4} \, \text{T} \)
Answer & Solution
Correct Answer
(A) \( 1.5 \times 10^{-4} \, \text{T} \)
Step-by-step Solution
Detailed explanation
\( F = ma \) \( F = qvB \) (as \( \vec{v} \perp \vec{B} \)) \( qvB = ma \) \( B = \frac{ma}{qv} \) \( B = \frac{(1.6 \times 10^{-27} \, \text{kg})(10^{12} \, \text{m/s}^2)}{(1.6 \times 10^{-19} \, \text{C})(2 \times 10^7 \, \text{m/s})} \)…
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