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CUET · PHYSICS · PYQ PAPER 2023

A proton is moving in a circular path in a magnetic field perpendicular to its plane. It possesses kinetic energy E. If the magnetic field increases to four times and the proton moves in same circular path, what will be kinetic energy?

  1. A 4E
  2. B 16E
  3. C E/2
  4. D E
Verified Solution

Answer & Solution

Correct Answer

(B) 16E

Step-by-step Solution

Detailed explanation

\(qvB = \frac{mv^2}{r} \Rightarrow v = \frac{qrB}{m}\) \(E = \frac{1}{2}mv^2 = \frac{1}{2}m \left(\frac{qrB}{m}\right)^2 = \frac{q^2r^2B^2}{2m}\) \(E' = \frac{q^2r^2(4B)^2}{2m} = 16 \frac{q^2r^2B^2}{2m} = 16E\)
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