CUET · PHYSICS · PYQ PAPER 2023
A proton is moving in a circular path in a magnetic field perpendicular to its plane. It possesses kinetic energy E. If the magnetic field increases to four times and the proton moves in same circular path, what will be kinetic energy?
- A 4E
- B 16E
- C E/2
- D E
Answer & Solution
Correct Answer
(B) 16E
Step-by-step Solution
Detailed explanation
\(qvB = \frac{mv^2}{r} \Rightarrow v = \frac{qrB}{m}\) \(E = \frac{1}{2}mv^2 = \frac{1}{2}m \left(\frac{qrB}{m}\right)^2 = \frac{q^2r^2B^2}{2m}\) \(E' = \frac{q^2r^2(4B)^2}{2m} = 16 \frac{q^2r^2B^2}{2m} = 16E\)
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