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CUET · PHYSICS · PYQ PAPER 2025

A proton and an alpha particle accelerated through different potential differences have the same de-Broglie wavelength. The ratio of their respective accelerating potentials is

  1. A 2 : 1
  2. B 8 : 1
  3. C 4 : 1
  4. D 1 : 1
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Answer & Solution

Correct Answer

(B) 8 : 1

Step-by-step Solution

Detailed explanation

\(\lambda = \frac{h}{\sqrt{2mqV}}\) \(\lambda_p = \lambda_\alpha \Rightarrow \sqrt{2m_p e V_p} = \sqrt{2m_\alpha q_\alpha V_\alpha}\) \(m_p e V_p = m_\alpha q_\alpha V_\alpha\) \(m_p e V_p = (4m_p)(2e) V_\alpha\) \(V_p = 8 V_\alpha\) \(\frac{V_p}{V_\alpha} = 8:1\)
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