CUET · PHYSICS · PYQ PAPER 2025
A proton and an alpha particle accelerated through different potential differences have the same de-Broglie wavelength. The ratio of their respective accelerating potentials is
- A 2 : 1
- B 8 : 1
- C 4 : 1
- D 1 : 1
Answer & Solution
Correct Answer
(B) 8 : 1
Step-by-step Solution
Detailed explanation
\(\lambda = \frac{h}{\sqrt{2mqV}}\) \(\lambda_p = \lambda_\alpha \Rightarrow \sqrt{2m_p e V_p} = \sqrt{2m_\alpha q_\alpha V_\alpha}\) \(m_p e V_p = m_\alpha q_\alpha V_\alpha\) \(m_p e V_p = (4m_p)(2e) V_\alpha\) \(V_p = 8 V_\alpha\) \(\frac{V_p}{V_\alpha} = 8:1\)
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