CUET · PHYSICS · PYQ PAPER 2025
A proton and a deuteron execute circular orbits having same radii of 0.5 m in a plane perpendicular to a uniform magnetic field B. If the kinetic energy of the deuteron is 50 keV, the K.E. of the proton will be
- A 200 keV
- B 100 keV
- C 50 keV
- D 25 keV
Answer & Solution
Correct Answer
(B) 100 keV
Step-by-step Solution
Detailed explanation
\( K = \frac{(qrB)^2}{2m} \) \( \frac{K_p}{K_d} = \frac{q_p^2 r_p^2 B^2 / (2m_p)}{q_d^2 r_d^2 B^2 / (2m_d)} \) \( \frac{K_p}{K_d} = \frac{q_p^2}{q_d^2} \cdot \frac{m_d}{m_p} \cdot \frac{r_p^2}{r_d^2} \)…
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