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CUET · PHYSICS · PYQ PAPER 2024

A proton accelerated through potential difference V has de Broglie wavelength \(\lambda\). On doubling the potential, the de Broglie wavelength of the proton :

  1. A remains unchanged
  2. B becomes double
  3. C becomes four times
  4. D decreases
Verified Solution

Answer & Solution

Correct Answer

(D) decreases

Step-by-step Solution

Detailed explanation

\(\lambda = \frac{h}{\sqrt{2mqV}}\) \(\lambda_1 = \frac{h}{\sqrt{2mqV}}\) \(\lambda_2 = \frac{h}{\sqrt{2mq(2V)}}\) \(\frac{\lambda_2}{\lambda_1} = \frac{1}{\sqrt{2}}\) decreases