CUET · PHYSICS · PYQ PAPER 2023
A potential difference of 3 V is applied across a conductor of resistance \(1.5 \Omega\).
The number of electrons flowing through it in one second would be:
(Given charge of an electron, \(e=1.6 \times 10^{-19} C\) )
- A \(16 \times 10^{19}\)
- B \(4.5 \times 10^{19}\)
- C \(1.25 \times 10^{19}\)
- D \(4.8 \times 10^{19}\)
Answer & Solution
Correct Answer
(C) \(1.25 \times 10^{19}\)
Step-by-step Solution
Detailed explanation
\(I = \frac{V}{R} = \frac{3}{1.5} = 2 \, A\) \(n = \frac{I \cdot t}{e} = \frac{2 \cdot 1}{1.6 \times 10^{-19}} = 1.25 \times 10^{19}\)
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