CUET · PHYSICS · PYQ PAPER 2023
A plane E-M wave of frequency 48 MHz travels in free space along the positive x-direction. At a particular point in space and time \( \vec{E} = 10.2\hat{j} \text{ V/m} \). The corresponding magnetic field \( \vec{B} \) at that point will be:
- A \( 3.4 \times 10^{-8}\hat{k} \text{ T} \)
- B \( -4.8 \times 10^{-8}\hat{k} \text{ T} \)
- C \( -3.4 \times 10^{-8}\hat{k} \text{ T} \)
- D \( 2.1 \times 10^{-7}\hat{k} \text{ T} \)
Answer & Solution
Correct Answer
(A) \( 3.4 \times 10^{-8}\hat{k} \text{ T} \)
Step-by-step Solution
Detailed explanation
\(B = E/c\) \(B = 10.2 / (3 \times 10^8) = 3.4 \times 10^{-8} \text{ T}\) Since \(\vec{E} \times \vec{B}\) is along the direction of propagation (\(\hat{i}\)), and \(\vec{E}\) is along \(\hat{j}\), then \(\hat{j} \times \vec{B}_{\text{direction}} = \hat{i}\). This implies…
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