CUET · PHYSICS · PYQ PAPER 2025
A particle of charge q and mass m moves in a circular orbit of radius r with angular speed \( \omega \). The ratio of the magnitude of its magnetic moment (m) to that of its angular momentum (L) depends on
- A m and \( \omega \) only
- B m and q only
- C m, \( \omega \) and q
- D \( \omega \) and q only
Answer & Solution
Correct Answer
(B) m and q only
Step-by-step Solution
Detailed explanation
\( m = (1/2) q \omega r^2 \) \( L = mr^2 \omega \) \( \frac{m}{L} = \frac{(1/2) q \omega r^2}{mr^2 \omega} = \frac{q}{2m} \) The ratio depends on m and q only.
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