CUET · PHYSICS · PYQ PAPER 2023
A \(\beta\)-particle is moving perpendicular to the uniform electric field created by a potential difference of \( 6 \times 10^3 \text{ V} \) across parallel metal plates separated by a distance of 6 cm. What is the acceleration of the beta particle between the plates? (Mass of electron = \( 9.1 \times 10^{-31} \text{ kg} \))
- A \( 1.76 \times 10^{14} \text{ m s}^{-2} \)
- B \( 1.76 \times 10^{16} \text{ m s}^{-2} \)
- C \( 1.8 \times 10^{-16} \text{ m s}^{-2} \)
- D \( 1.8 \times 10^{-12} \text{ m s}^{-2} \)
Answer & Solution
Correct Answer
(B) \( 1.76 \times 10^{16} \text{ m s}^{-2} \)
Step-by-step Solution
Detailed explanation
\( E = \frac{V}{d} = \frac{6 \times 10^3 \text{ V}}{0.06 \text{ m}} = 1 \times 10^5 \text{ V/m} \) \( a = \frac{qE}{m} = \frac{(1.6 \times 10^{-19} \text{ C}) \times (1 \times 10^5 \text{ V/m})}{9.1 \times 10^{-31} \text{ kg}} \)…
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