CUET · PHYSICS · PYQ PAPER 2023
A parallel plate capacitor whose capacitance C is 13.0 pF is charged by a battery to a potential difference V = 13.0 V between its plates. What is the potential energy of the capacitor ?
- A 1.098 nJ
- B 2197 pF
- C 1.98 pJ
- D 2.197 nJ
Answer & Solution
Correct Answer
(A) 1.098 nJ
Step-by-step Solution
Detailed explanation
\( U = \frac{1}{2} C V^2 \) \( U = \frac{1}{2} (13.0 \times 10^{-12} \text{ F}) (13.0 \text{ V})^2 \) \( U = 1.0985 \times 10^{-9} \text{ J} = 1.0985 \text{ nJ} \)
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