CUET · PHYSICS · PYQ PAPER 2023
A parallel plate capacitor made of circular plates each of radius 10.0 cm has a capacitance 200 pF . The capacitor is connected to a 200 V ac supply with an angular frequency of \(200 rad / s\). The amplitude of the current is :
- A \(8 \times 10^{-6} A\)
- B \(8 \times 10^{-7} A\)
- C \(11.3 \times 10^{-6} A\)
- D \(11.3 \times 10^{-7} A\)
Answer & Solution
Correct Answer
(C) \(11.3 \times 10^{-6} A\)
Step-by-step Solution
Detailed explanation
\(V_{peak} = V_{rms} \sqrt{2}\) \(V_{peak} = 200 \sqrt{2} \text{ V}\) \(I_0 = V_{peak} \omega C\) \(I_0 = (200 \sqrt{2}) (200) (200 \times 10^{-12})\) \(I_0 = 8 \sqrt{2} \times 10^{-6} \text{ A}\) \(I_0 \approx 11.3 \times 10^{-6} \text{ A}\)
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