A parallel plate capacitor is charged by battery. While the battery remains connected and dielectric slab of dielectric constant 'k' is inserted between the plates of capacitor then,
A. Charge increases and becomes k times.
B. Capacitance decreases becomes times 1/k
C. Energy stored in capacitor increases to \(k\) times.
D. Potential difference increases to \(k\) times.
Choose the correct answer from the options given below:

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.