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CUET · PHYSICS · PYQ PAPER 2023

A parallel plate capacitor having area A and separated by distance d is filled by copper plate of thickness b. The new capacitance is:

  1. A \(\frac{\epsilon_0 A}{d + 2b}\)
  2. B \(\frac{\epsilon_0 A}{2d}\)
  3. C \(\frac{\epsilon_0 A}{d - b}\)
  4. D \(\frac{2\epsilon_0 A}{d + 2b}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{\epsilon_0 A}{d - b}\)

Step-by-step Solution

Detailed explanation

Effective dielectric thickness: \(d' = d - b\) New capacitance: \(C = \frac{\epsilon_0 A}{d'} = \frac{\epsilon_0 A}{d - b}\)
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