CUET · PHYSICS · PYQ PAPER 2023
A parallel plate capacitor having area A and separated by distance d is filled by copper plate of thickness b. The new capacitance is:
- A \(\frac{\epsilon_0 A}{d + 2b}\)
- B \(\frac{\epsilon_0 A}{2d}\)
- C \(\frac{\epsilon_0 A}{d - b}\)
- D \(\frac{2\epsilon_0 A}{d + 2b}\)
Answer & Solution
Correct Answer
(C) \(\frac{\epsilon_0 A}{d - b}\)
Step-by-step Solution
Detailed explanation
Effective dielectric thickness: \(d' = d - b\) New capacitance: \(C = \frac{\epsilon_0 A}{d'} = \frac{\epsilon_0 A}{d - b}\)
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