CUET · PHYSICS · PYQ PAPER 2025
A nucleus \({ }_{92}^{238} X\) emits one alpha particle and then one beta particle (electron). The product nucleus will have
- A Atomic number \(=90\), Mass number \(=234\)
- B Atomic number \(=91\), Mass number \(=234\)
- C Atomic number \(=91\), Mass number \(=238\)
- D Atomic number \(=89\), Mass number \(=234\)
Answer & Solution
Correct Answer
(B) Atomic number \(=91\), Mass number \(=234\)
Step-by-step Solution
Detailed explanation
\({ }_{92}^{238} X \xrightarrow{\alpha} { }_{90}^{234} Y\) (mass number \(238-4=234\), atomic number \(92-2=90\)) \({ }_{90}^{234} Y \xrightarrow{\beta^{-}} { }_{91}^{234} P\) (mass number \(234-0=234\), atomic number \(90-(-1)=91\)) Atomic number \(=91\), Mass number \(=234\)
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