CUET · PHYSICS · PYQ PAPER 2023
A moving coil galvanometer has a resistance of 40 \( \Omega \). It gives a full scale deflection with a current of 2 mA. How is to be modified to convert it to a voltmeter of 5 V range?
- A \( 1230 \, \Omega \) connected in series with galvanometer
- B \( 2460 \, \Omega \) connected in series with galvanometer
- C \( 1230 \, \Omega \) connected in parallel with galvanometer
- D \( 2460 \, \Omega \) connected in parallel with galvanometer
Answer & Solution
Correct Answer
(B) \( 2460 \, \Omega \) connected in series with galvanometer
Step-by-step Solution
Detailed explanation
\( R_s = \frac{V}{I_g} - R_g \) \( R_s = \frac{5 \, \text{V}}{2 \times 10^{-3} \, \text{A}} - 40 \, \Omega \) \( R_s = 2500 \, \Omega - 40 \, \Omega \) \( R_s = 2460 \, \Omega \) 2460 \(\Omega\) connected in series with galvanometer.
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