CUET · PHYSICS · PYQ PAPER 2025
A moving coil galvanometer has 100 equal divisions. Its current sensitivity is 20 divisions per mA and voltage sensitivity is 4 divisions per mV. To convert it into a voltmeter in which each division reads 1 V, the resistance needed to be connected in series with the coil will be :
- A \( 9995 \text{ } \Omega \)
- B \( 19995 \text{ } \Omega \)
- C \( 995 \text{ } \Omega \)
- D \( 4995 \text{ } \Omega \)
Answer & Solution
Correct Answer
(B) \( 19995 \text{ } \Omega \)
Step-by-step Solution
Detailed explanation
\(I_g = \frac{100 \text{ div}}{20 \text{ div/mA}} = 5 \text{ mA} = 5 \times 10^{-3} \text{ A}\) \(V_g = \frac{100 \text{ div}}{4 \text{ div/mV}} = 25 \text{ mV} = 25 \times 10^{-3} \text{ V}\)…
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