CUET · PHYSICS · PYQ PAPER 2023
A metallic wire of resistance \( R \) and resistivity \( \rho \) is cut into six equal parts. Now each part is stretched to six times its length. The new resistance and resistivity of each part will be :
- A \( 6R \text{ and } 6\rho \)
- B \( 36R \text{ and } 6\rho \)
- C \( 6R \text{ and } \rho \)
- D \( R \text{ and } \rho \)
Answer & Solution
Correct Answer
(C) \( 6R \text{ and } \rho \)
Step-by-step Solution
Detailed explanation
Resistance of 1 part after cutting: \( R_p = \rho \frac{L/6}{A} = \frac{R}{6} \) Stretching factor: \( k = 6 \) New resistance of each part: \( R'_{p} = k^2 R_p = (6)^2 \left( \frac{R}{6} \right) = 36 \frac{R}{6} = 6R \) New resistivity: \( \rho \)
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