CUET · PHYSICS · PYQ PAPER 2025
A metal foil of thickness (3/4)d is introduced between two plates of a capacitor of capacitance C. The distance between the plates of the capacitor is d. The new capacitance of the capacitor will be
- A 2 C
- B C/2
- C C
- D 4 C
Answer & Solution
Correct Answer
(D) 4 C
Step-by-step Solution
Detailed explanation
\( d' = d - t \) \( d' = d - \frac{3}{4}d = \frac{1}{4}d \) \( C' = \frac{\epsilon_0 A}{d'} \) \( C' = \frac{\epsilon_0 A}{\frac{1}{4}d} = 4 \frac{\epsilon_0 A}{d} \) \( C' = 4C \)
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