CUET · PHYSICS · PYQ PAPER 2023
A long straight wire carries a current of 35 A. The magnitude of the field \( \vec{B} \) at a point 20 cm from the wire would be:
- A \( 5.3 \times 10^{-5} \text{ T} \)
- B \( 3.5 \times 10^{-6} \text{ T} \)
- C \( 3.5 \times 10^{-5} \text{ T} \)
- D \( 53 \times 10^{-7} \text{ T} \)
Answer & Solution
Correct Answer
(C) \( 3.5 \times 10^{-5} \text{ T} \)
Step-by-step Solution
Detailed explanation
\( B = \frac{\mu_0 I}{2\pi r} \) \( B = \frac{(4\pi \times 10^{-7} \text{ T} \cdot \text{m/A})(35 \text{ A})}{2\pi (0.20 \text{ m})} \) \( B = 3.5 \times 10^{-5} \text{ T} \)
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