CUET · PHYSICS · PYQ PAPER 2025
A light of wavelength of \( \lambda = 6 \times 10^{-7} \text{ m} \) illuminates a single slit of width \( a = 1.2 \text{ mm} \). The screen is at a distance of \( D = 2.4 \text{ m} \) away from the slit. The width of central maximum (\( \beta_0 \)) is
- A 2.4 mm
- B 1.2 mm
- C 3.5 mm
- D 4.8 mm
Answer & Solution
Correct Answer
(A) 2.4 mm
Step-by-step Solution
Detailed explanation
\( \beta_0 = \frac{2 \lambda D}{a} \) \( = \frac{2 \times (6 \times 10^{-7} \text{ m}) \times (2.4 \text{ m})}{1.2 \times 10^{-3} \text{ m}} = 2.4 \times 10^{-3} \text{ m} = 2.4 \text{ mm} \)
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