CUET · PHYSICS · PYQ PAPER 2025
A light of wavelength 500 nm falls on a metal surface, whose work function is 2.14 eV. The kinetic energy of the emitted electrons is
- A 3.4 eV
- B 0.34 eV
- C 2.48 eV
- D 0.034 eV
Answer & Solution
Correct Answer
(B) 0.34 eV
Step-by-step Solution
Detailed explanation
\(E = \frac{1240}{\lambda}\) \(E = \frac{1240}{500} \text{ eV} = 2.48 \text{ eV}\) \(KE = E - \phi\) \(KE = 2.48 \text{ eV} - 2.14 \text{ eV}\) \(KE = 0.34 \text{ eV}\)
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