CUET · PHYSICS · PYQ PAPER 2023
A heater coil is rated 100 W, 200 V. It is cut into two identical parts. Both parts are connected together in parallel to the same source of 200 V. The energy liberated per second in the new combination is:
- A 200 W
- B 380 W
- C 400 W
- D 520 W
Answer & Solution
Correct Answer
(C) 400 W
Step-by-step Solution
Detailed explanation
\(R = \frac{V^2}{P}\) \(R = \frac{(200 \text{ V})^2}{100 \text{ W}} = 400 \text{ \(\Omega\)}\) \(R_1 = R_2 = \frac{R}{2} = \frac{400 \text{ \(\Omega\)}}{2} = 200 \text{ \(\Omega\)}\) \(R_{eq} = \frac{R_1 \times R_2}{R_1 + R_2} = \frac{200 \text{…
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