CUET · PHYSICS · PYQ PAPER 2023
A heater boils \( x \) amount of water in time \( t_{1} \) and another heater boils the same water in time \( t_{2} \) having resistances \( R_{1} \) and \( R_{2} \) respectively. The ratio \( \frac{t_{1}}{t_{2}} \) will be:
- A \( \left( \frac{R_{1}}{R_{2}} \right)^{2} \)
- B \( \left( \frac{R_{2}}{R_{1}} \right)^{2} \)
- C \( \frac{R_{2}}{R_{1}} \)
- D \( \frac{R_{1}}{R_{2}} \)
Answer & Solution
Correct Answer
(D) \( \frac{R_{1}}{R_{2}} \)
Step-by-step Solution
Detailed explanation
\( Q = \frac{V^2}{R}t \) \( \frac{V^2}{R_1}t_1 = \frac{V^2}{R_2}t_2 \) \( \frac{t_1}{t_2} = \frac{R_1}{R_2} \)
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