CUET · PHYSICS · PYQ PAPER 2023
A glass beaker contains water upto a height \( h_1 \) and kerosene oil above water upto height \( h_2 \). If the refractive index of water is \( \mu_w \) and that of oil is \( \mu_k \), then what will be the apparent shift in the position of the bottom of the beaker when viewed from above ?
- A \( \left[ \left( 1 - \frac{1}{\mu_w} \right) + \left( 1 - \frac{1}{\mu_k} \right) \right] (h_1 + h_2) \)
- B \( \left( 1 - \frac{1}{\mu_k} \right) h_1 + \left( 1 - \frac{1}{\mu_w} \right) h_1 \)
- C \( \left( 1 - \frac{1}{\mu_w} \right) h_2 + \left( 1 - \frac{1}{\mu_k} \right) h_1 \)
- D \( \left( 1 - \frac{1}{\mu_w} \right) h_1 + \left( 1 - \frac{1}{\mu_k} \right) h_2 \)
Answer & Solution
Correct Answer
(D) \( \left( 1 - \frac{1}{\mu_w} \right) h_1 + \left( 1 - \frac{1}{\mu_k} \right) h_2 \)
Step-by-step Solution
Detailed explanation
Shift due to water: \( \Delta h_w = h_1 \left( 1 - \frac{1}{\mu_w} \right) \) Shift due to kerosene: \( \Delta h_k = h_2 \left( 1 - \frac{1}{\mu_k} \right) \) Total shift:…
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