CUET · PHYSICS · PYQ PAPER 2023
A generator develops an e.m.f of 150 V and has a terminal potential difference of 125 V, when the armature current is 50 A, the resistance of armature will be
- A 3 \(\Omega\)
- B 0.5 \(\Omega\)
- C 2.5 \(\Omega\)
- D 2 \(\Omega\)
Answer & Solution
Correct Answer
(B) 0.5 \(\Omega\)
Step-by-step Solution
Detailed explanation
\( V = E - IR_a \) \( R_a = \frac{E - V}{I} \) \( R_a = \frac{150 V - 125 V}{50 A} = \frac{25 V}{50 A} = 0.5 \, \Omega \)
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