CUET · PHYSICS · PYQ PAPER 2023
A galvanometer of resistance G is converted into a voltmeter to measure upto V volts by connecting a resistance \( R_1 \) in series with the coil. If a resistance \( R_2 \) is connected in series with it, then it can measure the \( \frac{V}{3} \) volts. Find the resistance \( R_3 \) in terms of \( R_1 \) and \( R_2 \) required to be connected to convert it into a voltmeter that can read upto 3V volts :
- A \( 4R_1 - 3R_2 \)
- B \( 3R_1 - 2R_2 \)
- C \( 4R_1 + 3R_2 \)
- D \( 3R_1 + 2R_2 \)
Answer & Solution
Correct Answer
(A) \( 4R_1 - 3R_2 \)
Step-by-step Solution
Detailed explanation
\( V = I_g(G + R_1) \) \( \frac{V}{3} = I_g(G + R_2) \) \( \frac{V}{V/3} = \frac{G+R_1}{G+R_2} \Rightarrow 3 = \frac{G+R_1}{G+R_2} \) \( 3(G+R_2) = G+R_1 \Rightarrow 3G + 3R_2 = G + R_1 \) \( 2G = R_1 - 3R_2 \) \( 3V = I_g(G + R_3) \)…
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