CUET · PHYSICS · PYQ PAPER 2023
A galvanometer of \( 60 \, \Omega \) resistance shows full scale deflection for a current of 8 mA. The shunt required to convert the galvanometer into an ammeter of range 0 to 6 A will be :
- A \(4.67 \times 10^{-2} \, \Omega \)
- B \(5.67 \times 10^{-2} \, \Omega \)
- C \(2.67 \times 10^{-2} \, \Omega \)
- D \(8 \times 10^{-2} \, \Omega \)
Answer & Solution
Correct Answer
(D) \(8 \times 10^{-2} \, \Omega \)
Step-by-step Solution
Detailed explanation
\( R_s = \frac{I_g R_g}{I - I_g} \) \( R_s = \frac{(8 \times 10^{-3} \, \text{A})(60 \, \Omega)}{6 \, \text{A} - 8 \times 10^{-3} \, \text{A}} \) \( R_s = \frac{0.48}{5.992} \) \( R_s \approx 8 \times 10^{-2} \, \Omega \)
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