CUET · PHYSICS · PYQ PAPER 2023
A galvanometer has a resistance of 8 \( \Omega \). It is shunted by a wire of resistance 2 \( \Omega \). If the total current is 2 A, the current passing through the shunt is
- A 1.6 A
- B 1 A
- C 2 A
- D 0.5 A
Answer & Solution
Correct Answer
(A) 1.6 A
Step-by-step Solution
Detailed explanation
\(I_s = I_{total} \frac{R_g}{R_s + R_g}\) \(I_s = 2 \, A \times \frac{8 \, \Omega}{2 \, \Omega + 8 \, \Omega} = 1.6 \, A\)
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