CUET · PHYSICS · PYQ PAPER 2025
A galvanometer has a resistance of \(8 \Omega\). It is shunted by a wire of resistance \(2 \Omega\). If the total current is 2 A, the current passing through the shunt is
- A \(1.6 A\)
- B \(1 A\)
- C \(2 A\)
- D \(0.5 A\)
Answer & Solution
Correct Answer
(A) \(1.6 A\)
Step-by-step Solution
Detailed explanation
\( I_s = I_t \left( \frac{R_g}{R_g + R_s} \right) \) \( I_s = 2 \, A \left( \frac{8 \, \Omega}{8 \, \Omega + 2 \, \Omega} \right) \) \( I_s = 1.6 \, A \)
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