CUET · PHYSICS · PYQ PAPER 2025
A Fraunhofer diffraction pattern due to a single slit of width 0.2 mm is being obtained on a screen placed at a distance of 2 m from the slit. The first minimum lies at 5 mm on either side of the central maximum on the screen. The wavelength of light is:
- A 4700 Å
- B 5000 Å
- C 6000 Å
- D 6800 Å
Answer & Solution
Correct Answer
(B) 5000 Å
Step-by-step Solution
Detailed explanation
\(\lambda = \frac{ay_1}{D}\) \(\lambda = \frac{(0.2 \times 10^{-3} \, \text{m})(5 \times 10^{-3} \, \text{m})}{2 \, \text{m}}\) \(\lambda = 5 \times 10^{-7} \, \text{m}\) \(\lambda = 5000 \, \text{Å}\)
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