CUET · PHYSICS · PYQ PAPER 2025
A difference of 2.21 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom makes a transition from the upper level to the lower level?
- A \( 5.3 \times 10^{14} \, \text{Hz} \)
- B \( 2.3 \times 10^{14} \, \text{Hz} \)
- C \( 8 \times 10^{14} \, \text{Hz} \)
- D \( 3 \times 10^{14} \, \text{Hz} \)
Answer & Solution
Correct Answer
(A) \( 5.3 \times 10^{14} \, \text{Hz} \)
Step-by-step Solution
Detailed explanation
\( E = hf \Rightarrow f = E/h \) \( f = (2.21 \, \text{eV} \times 1.602 \times 10^{-19} \, \text{J/eV}) / (6.626 \times 10^{-34} \, \text{J} \cdot \text{s}) \) \( f \approx 5.34 \times 10^{14} \, \text{Hz} \)
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