CUET · PHYSICS · PYQ PAPER 2025
A current of 2 A flows through a 2 \( \Omega \) resistor when connected with a cell. When the resistance is replaced by 10 \( \Omega \), a current of 0.5 A flows. The internal resistance of the cell is
- A 1/3 \( \Omega \)
- B 1 \( \Omega \)
- C 3/2 \( \Omega \)
- D 2/3 \( \Omega \)
Answer & Solution
Correct Answer
(D) 2/3 \( \Omega \)
Step-by-step Solution
Detailed explanation
\(E = I_1(R_1+r) \Rightarrow E = 2(2+r)\) \(E = I_2(R_2+r) \Rightarrow E = 0.5(10+r)\) \(2(2+r) = 0.5(10+r)\) \(4+2r = 5+0.5r\) \(1.5r = 1\) \(r = \frac{1}{1.5} = \frac{2}{3} \, \Omega\)
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