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CUET · PHYSICS · PYQ PAPER 2025

A current of 15 A flows in a wire of cross-sectional area \( 5 \text{ mm}^2 \) with a drift velocity of \( 3 \times 10^{-3} \text{ m/s} \). The electron density in the wire will be :

  1. A \( 489 \times 10^{25} \text{ m}^{-3} \)
  2. B \( 546 \times 10^{25} \text{ m}^{-3} \)
  3. C \( 725 \times 10^{23} \text{ m}^{-3} \)
  4. D \( 625 \times 10^{25} \text{ m}^{-3} \)
Verified Solution

Answer & Solution

Correct Answer

(D) \( 625 \times 10^{25} \text{ m}^{-3} \)

Step-by-step Solution

Detailed explanation

\( n = \frac{I}{e A v_d} \) \( n = \frac{15}{(1.6 \times 10^{-19})(5 \times 10^{-6})(3 \times 10^{-3})} \) \( n = \frac{15}{24 \times 10^{-28}} \) \( n = 0.625 \times 10^{28} \) \( n = 625 \times 10^{25} \text{ m}^{-3} \)