CUET · PHYSICS · PYQ PAPER 2025
A current is uniformly distributed across the cross-section of cylindrical wire of radius R = 4 mm with current density \( J = 2.5 \times 10^5 \text{ Am}^{-2} \). The amount of current flowing through the outer portion of the wire between radial distance R/2 and R is
- A 9.18 A
- B 94.2 A
- C 9.42 A
- D 7.28 A
Answer & Solution
Correct Answer
(C) 9.42 A
Step-by-step Solution
Detailed explanation
\(I = \int_{R/2}^{R} J (2 \pi r dr)\) \(I = J \cdot 2 \pi \left[ \frac{r^2}{2} \right]_{R/2}^{R}\) \(I = J \cdot 2 \pi \left( \frac{R^2}{2} - \frac{(R/2)^2}{2} \right) = J \cdot 2 \pi \left( \frac{R^2}{2} - \frac{R^2}{8} \right) = J \cdot \frac{3 \pi R^2}{4}\)…
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