CUET · PHYSICS · PYQ PAPER 2025
A copper wire of area of cross-section \( 2 \times 10^{-6} \, \text{m}^2 \) and electron density \( 10^{28} \, \text{m}^{-3} \) carries a current of 1.6 A. Time taken by an electron to drift from one end of a 1.0 m long wire to its other end will be
- A \( 2 \times 10^3 \, \text{s} \)
- B \( 10^3 \, \text{s} \)
- C \( 2 \times 10^{-3} \, \text{s} \)
- D \( 1 \times 10^{-3} \, \text{s} \)
Answer & Solution
Correct Answer
(A) \( 2 \times 10^3 \, \text{s} \)
Step-by-step Solution
Detailed explanation
\( v_d = \frac{I}{nAe} = \frac{1.6}{10^{28} \times 2 \times 10^{-6} \times 1.6 \times 10^{-19}} = 5 \times 10^{-4} \, \text{m/s} \) \( t = \frac{L}{v_d} = \frac{1.0}{5 \times 10^{-4}} = 2 \times 10^3 \, \text{s} \)
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