CUET · PHYSICS · PYQ PAPER 2023
A coil of inductance 0.50 H and resistance 100 \( \Omega \) is connected to 240 V, 50 Hz supply. The maximum current in the coil is:
- A 1.72 A
- B 1.62 A
- C 1.82 A
- D 1.92 A
Answer & Solution
Correct Answer
(C) 1.82 A
Step-by-step Solution
Detailed explanation
\(X_L = 2 \pi f L = 2 \pi (50 \text{ Hz})(0.50 \text{ H}) = 157.08 \, \Omega\) \(Z = \sqrt{R^2 + X_L^2} = \sqrt{(100 \, \Omega)^2 + (157.08 \, \Omega)^2} = 186.21 \, \Omega\) \(I_{rms} = \frac{V_{rms}}{Z} = \frac{240 \text{ V}}{186.21 \, \Omega} = 1.2888 \, \text{A}\)…
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