CUET · PHYSICS · PYQ PAPER 2025
A coil has an inductance of \( L = 0.02 \text{ H} \) and the current is increasing at the rate of \( \frac{dI}{dt} = 200 \text{ A/s} \). The emf induced in it, \( \epsilon \), is:
- A - 2 V
- B - 4 V
- C + 4 V
- D + 6 V
Answer & Solution
Correct Answer
(B) - 4 V
Step-by-step Solution
Detailed explanation
\( \epsilon = -L \frac{dI}{dt} \) \( \epsilon = -(0.02 \text{ H})(200 \text{ A/s}) \) \( \epsilon = -4 \text{ V} \)
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