CUET · PHYSICS · PYQ PAPER 2023
A closely wound solenoid of 1000 turns and area of cross section \( 1.2 \text{ cm}^2 \) carries a current of 5 A. It is suspended horizontally in uniform magnetic field of \( 5 \times 10^{-2} \text{ T} \) making an angle of \( 30^\circ \) with the axis of solenoid. The torque acting on the solenoid is:
- A \( 1.5 \times 10^{-2} \text{ N m} \)
- B \( 3 \times 10^{-5} \text{ N m} \)
- C \( 1.8 \times 10^{-3} \text{ N m} \)
- D \( 1.5 \times 10^{-4} \text{ N m} \)
Answer & Solution
Correct Answer
(A) \( 1.5 \times 10^{-2} \text{ N m} \)
Step-by-step Solution
Detailed explanation
\( \tau = NIAB \sin\theta \) \( \tau = 1000 \times 5 \times (1.2 \times 10^{-4}) \times (5 \times 10^{-2}) \times \sin(30^\circ) \) \( \tau = 1.5 \times 10^{-2} \text{ N m} \)
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