CUET · PHYSICS · PYQ PAPER 2025
A circular loop of area \( A = 0.01 \text{ m}^2 \) carrying a current of \( I = 10 \text{ A} \), is held in a magnetic field of \( B = 0.1 \text{ T} \) parallel to the plane of the loop. The torque acting on the loop is-
- A 0.001 N m
- B 0.01 N m
- C 0.1 N m
- D zero
Answer & Solution
Correct Answer
(B) 0.01 N m
Step-by-step Solution
Detailed explanation
\( \mu = IA = (10 \text{ A})(0.01 \text{ m}^2) = 0.1 \text{ A m}^2 \) \( \tau = \mu B \sin \theta = (0.1 \text{ A m}^2)(0.1 \text{ T}) \sin 90^\circ = 0.01 \text{ N m} \)
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