CUET · PHYSICS · PYQ PAPER 2023
A circular loop of area \(1 cm^2\), carrying a current of 10 A , is placed in a magnetic field of 0.1 T perpendicular to the plane of the loop. The torque on the loop due to the magnetic field is :
- A zero
- B \(10^{-4} Nm\)
- C \(10^{-2} Nm\)
- D 1 Nm
Answer & Solution
Correct Answer
(A) zero
Step-by-step Solution
Detailed explanation
\( \tau = IAB \sin\theta \) \( \tau = (10 \, A)(1 \times 10^{-4} \, m^2)(0.1 \, T) \sin(0^\circ) \) \( \tau = 0 \)
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