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CUET · PHYSICS · PYQ PAPER 2023

A circular loop of area \(1 cm^2\), carrying a current of 10 A , is placed in a magnetic field of 0.1 T perpendicular to the plane of the loop. The torque on the loop due to the magnetic field is :

  1. A zero
  2. B \(10^{-4} Nm\)
  3. C \(10^{-2} Nm\)
  4. D 1 Nm
Verified Solution

Answer & Solution

Correct Answer

(A) zero

Step-by-step Solution

Detailed explanation

\( \tau = IAB \sin\theta \) \( \tau = (10 \, A)(1 \times 10^{-4} \, m^2)(0.1 \, T) \sin(0^\circ) \) \( \tau = 0 \)