CUET · PHYSICS · PYQ PAPER 2025
A circular loop of area \(0.02 m^2\) carrying a current of 5 A is held with its plane normal to a magnetic field of 0.2 T. The torque acting on the loop is
- A 0.002 N m
- B 0.02 N m
- C 0.2 N m
- D 0
Answer & Solution
Correct Answer
(D) 0
Step-by-step Solution
Detailed explanation
\( \tau = IAB \sin\theta \) \( \tau = (5 \, A)(0.02 \, m^2)(0.2 \, T) \sin 0^\circ \) \( \tau = 0 \)
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