CUET · PHYSICS · PYQ PAPER 2023
A circular coil of 20 turns and radius 10 cm is placed in a uniform magnetic field of 0.10 T normal to the plane of the coil. If the current in the coil is 5 A . The total torque on the coil is :
- A \(3.14 \times 10^{-3} Nm\)
- B \(3.14 \times 10^{-2} Nm\)
- C 3.14 Nm
- D Zero
Answer & Solution
Correct Answer
(D) Zero
Step-by-step Solution
Detailed explanation
\( \tau = NIAB \sin\theta \) \( \text{Since the magnetic field is normal to the plane of the coil, } \theta = 0^\circ \) \( \tau = (20)(5 \text{ A})(\pi (0.1 \text{ m})^2)(0.10 \text{ T}) \sin(0^\circ) \) \( \tau = 0 \text{ Nm} \)
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