CUET · PHYSICS · PYQ PAPER 2025
A charged particle moves along a circular path in a uniform magnetic field of 0.04 T with a velocity of \( 2 \times 10^5 \text{ m/s} \). The charge to mass ratio of the particle is \( 5 \times 10^7 \text{ C/kg} \). The radius of the circular path of the charged particle is:
- A 1000 cm
- B 10 cm
- C 50 cm
- D 100 cm
Answer & Solution
Correct Answer
(B) 10 cm
Step-by-step Solution
Detailed explanation
\( r = \frac{mv}{qB} = \frac{v}{(q/m)B} \) \( r = \frac{2 \times 10^5 \text{ m/s}}{(5 \times 10^7 \text{ C/kg})(0.04 \text{ T})} \) \( r = 0.1 \text{ m} \) \( r = 10 \text{ cm} \)
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