CUET · PHYSICS · PYQ PAPER 2025
A cell of emf \( \mathcal{E} = 10 \text{ V} \) and internal resistance \( r = 3 \Omega \) is connected to a uniform wire of length \( L = 500 \text{ cm} \) and resistance \( R = 3 \Omega \). The drop of potential with length in the wire is:
- A 30 mV/cm
- B 20 mV/cm
- C 10 mV/cm
- D 5 mV/cm
Answer & Solution
Correct Answer
(C) 10 mV/cm
Step-by-step Solution
Detailed explanation
\( I = \frac{\mathcal{E}}{R+r} = \frac{10 \text{ V}}{3 \Omega + 3 \Omega} = \frac{5}{3} \text{ A} \) \( V_{wire} = I \cdot R = \frac{5}{3} \text{ A} \cdot 3 \Omega = 5 \text{ V} \)…
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