CUET · PHYSICS · PYQ PAPER 2024
A cell of emf 1.1 V and internal resistance 0.5 \(\Omega\) is connected to a 0.5 \(\Omega\) wire. Another cell of same emf is added in series, but current remains unchanged. The second cell's internal resistance is :
- A 1 \(\Omega\)
- B 2.5 \(\Omega\)
- C 1.5 \(\Omega\)
- D 2 \(\Omega\)
Answer & Solution
Correct Answer
(A) 1 \(\Omega\)
Step-by-step Solution
Detailed explanation
\(I_1 = \frac{1.1}{0.5 + 0.5} = 1.1 \text{ A}\) \(I_2 = \frac{1.1 + 1.1}{0.5 + (0.5 + r_2)}\) \(1.1 = \frac{2.2}{1 + r_2}\) \(1 + r_2 = \frac{2.2}{1.1} = 2\) \(r_2 = 2 - 1 = 1 \text{ } \Omega\)
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