CUET · PHYSICS · PYQ PAPER 2025

A capacitor of capacitance C is first charged by a battery of V volts. It is disconnected from the battery and is filled with a dielectric of dielectric constant K. The ratio of energy stored in the two cases, respectively will be

A K : 1
B \( K^2 : 1 \)
C \( \sqrt{K} : 1 \)
D 1 : K

Verified Solution

Answer & Solution

Correct Answer

(A) K : 1

Step-by-step Solution

Detailed explanation

Energy initially: \( U_1 = \frac{1}{2}CV^2 \) Charge remains constant: \( Q = CV \) New capacitance: \( C' = KC \) Energy finally: \( U_2 = \frac{Q^2}{2C'} = \frac{(CV)^2}{2KC} = \frac{C^2V^2}{2KC} = \frac{CV^2}{2K} \) Ratio…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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