CUET · PHYSICS · PYQ PAPER 2025
A capacitor of capacitance \( C = 10 \text{ } \mu\text{F} \) is charged by connecting it to a battery of emf 12 V. The capacitor is now disconnected and reconnected to the battery with the polarity reversed. The heat developed in the connecting wires will be:
- A 2.88 mJ
- B 1.44 mJ
- C 0.72 mJ
- D 0.36 mJ
Answer & Solution
Correct Answer
(A) 2.88 mJ
Step-by-step Solution
Detailed explanation
\( H = 2CV^2 \) \( H = 2(10 \times 10^{-6} \text{ F})(12 \text{ V})^2 \) \( H = 2(10 \times 10^{-6})(144) \) \( H = 2880 \times 10^{-6} \text{ J} \) \( H = 2.88 \text{ mJ} \)
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