CUET · PHYSICS · PYQ PAPER 2025
A body of mass 20 g and charge \( +50 \text{ }\mu\text{C} \) is suspended from the ceiling by a string. A horizontal electric field of 10 kV/m is applied.
The angle between the string and the vertical direction is :
- A \( \tan^{-1}(2.50) \)
- B \( \tan^{-1}(3.00) \)
- C \( \tan^{-1}(3.50) \)
- D \( \sin^{-1}(2.50) \)
Answer & Solution
Correct Answer
(A) \( \tan^{-1}(2.50) \)
Step-by-step Solution
Detailed explanation
\( \tan \theta = \frac{qE}{mg} \) \( \tan \theta = \frac{(50 \times 10^{-6} \text{ C})(10 \times 10^3 \text{ V/m})}{(20 \times 10^{-3} \text{ kg})(10 \text{ m/s}^2)} \) \( \tan \theta = 2.5 \) \( \theta = \tan^{-1}(2.50) \)
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