CUET · PHYSICS · PYQ PAPER 2023
A bar magnet falls freely from a height of 9.8 m through a metal ring. Its acceleration will be equal to
- A zero
- B equal to \( 9.8 \text{ m/s}^2 \)
- C more than \( 9.8 \text{ m/s}^2 \)
- D less than \( 9.8 \text{ m/s}^2 \)
Answer & Solution
Correct Answer
(D) less than \( 9.8 \text{ m/s}^2 \)
Step-by-step Solution
Detailed explanation
Due to Lenz's law, an opposing magnetic force acts upwards on the falling magnet. This upward force reduces the net downward force on the magnet. Therefore, its acceleration \( a Thus, \( a < 9.8 \text{ m/s}^2 \).
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