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CUET · PHYSICS · PYQ PAPER 2025

A 400 pF capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 400 pF capacitor. The electrostatic energy lost in the process is

  1. A \( 2.4 \times 10^{-6} \text{ J} \)
  2. B \( 4.\times 10^{-6} \text{ J} \)
  3. C \( 6.0 \times 10^{-6} \text{ J} \)
  4. D \( 8.0 \times 10^{-6} \text{ J} \)
Verified Solution

Answer & Solution

Correct Answer

(B) \( 4.\times 10^{-6} \text{ J} \)

Step-by-step Solution

Detailed explanation

\(U_{lost} = \frac{1}{4} C V^2\) \(U_{lost} = \frac{1}{4} (400 \times 10^{-12} \text{ F})(200 \text{ V})^2\) \(U_{lost} = 4 \times 10^{-6} \text{ J}\)
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